Base | Representation |
---|---|
bin | 10100111000100101… |
… | …10101111110101001 |
3 | 1001221101120201010212 |
4 | 22130102311332221 |
5 | 140430300314402 |
6 | 5052322350505 |
7 | 544563306302 |
oct | 123422657651 |
9 | 31841521125 |
10 | 11212119977 |
11 | 4833a49763 |
12 | 220aabb435 |
13 | 1098b66426 |
14 | 7851297a9 |
15 | 4594de952 |
hex | 29c4b5fa9 |
11212119977 has 2 divisors, whose sum is σ = 11212119978. Its totient is φ = 11212119976.
The previous prime is 11212119917. The next prime is 11212119979. The reversal of 11212119977 is 77991121211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10601585296 + 610534681 = 102964^2 + 24709^2 .
It is a cyclic number.
It is not a de Polignac number, because 11212119977 - 224 = 11195342761 is a prime.
Together with 11212119979, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (11212119979) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606059988 + 5606059989.
It is an arithmetic number, because the mean of its divisors is an integer number (5606059989).
Almost surely, 211212119977 is an apocalyptic number.
It is an amenable number.
11212119977 is a deficient number, since it is larger than the sum of its proper divisors (1).
11212119977 is an equidigital number, since it uses as much as digits as its factorization.
11212119977 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 15876, while the sum is 41.
The spelling of 11212119977 in words is "eleven billion, two hundred twelve million, one hundred nineteen thousand, nine hundred seventy-seven".
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