Base | Representation |
---|---|
bin | 10100111000100101… |
… | …10101111111000011 |
3 | 1001221101120201011211 |
4 | 22130102311333003 |
5 | 140430300320003 |
6 | 5052322350551 |
7 | 544563306340 |
oct | 123422657703 |
9 | 31841521154 |
10 | 11212120003 |
11 | 4833a49787 |
12 | 220aabb457 |
13 | 1098b66446 |
14 | 7851297c7 |
15 | 4594de96d |
hex | 29c4b5fc3 |
11212120003 has 4 divisors (see below), whose sum is σ = 12813851440. Its totient is φ = 9610388568.
The previous prime is 11212119979. The next prime is 11212120033. The reversal of 11212120003 is 30002121211.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30002121211 = 59 ⋅508510529.
It is a cyclic number.
It is not a de Polignac number, because 11212120003 - 233 = 2622185411 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11212120033) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 800865708 + ... + 800865721.
It is an arithmetic number, because the mean of its divisors is an integer number (3203462860).
Almost surely, 211212120003 is an apocalyptic number.
11212120003 is a deficient number, since it is larger than the sum of its proper divisors (1601731437).
11212120003 is an equidigital number, since it uses as much as digits as its factorization.
11212120003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1601731436.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 11212120003 its reverse (30002121211), we get a palindrome (41214241214).
The spelling of 11212120003 in words is "eleven billion, two hundred twelve million, one hundred twenty thousand, three".
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