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1121212001153 is a prime number
BaseRepresentation
bin10000010100001101011…
…100010110101110000001
310222012001012012002000002
4100110031130112232001
5121332220233014103
62215024440205345
7144001451522336
oct20241534265601
93865035162002
101121212001153
113a2559a43462
1216136b769855
13819645b9a4a
143c3a472498d
151e272d28488
hex1050d716b81

1121212001153 has 2 divisors, whose sum is σ = 1121212001154. Its totient is φ = 1121212001152.

The previous prime is 1121212001111. The next prime is 1121212001179. The reversal of 1121212001153 is 3511002121211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1079870132224 + 41341868929 = 1039168^2 + 203327^2 .

It is a cyclic number.

It is not a de Polignac number, because 1121212001153 - 212 = 1121211997057 is a prime.

It is not a weakly prime, because it can be changed into another prime (1121212001353) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560606000576 + 560606000577.

It is an arithmetic number, because the mean of its divisors is an integer number (560606000577).

Almost surely, 21121212001153 is an apocalyptic number.

It is an amenable number.

1121212001153 is a deficient number, since it is larger than the sum of its proper divisors (1).

1121212001153 is an equidigital number, since it uses as much as digits as its factorization.

1121212001153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120, while the sum is 20.

Adding to 1121212001153 its reverse (3511002121211), we get a palindrome (4632214122364).

The spelling of 1121212001153 in words is "one trillion, one hundred twenty-one billion, two hundred twelve million, one thousand, one hundred fifty-three".