Base | Representation |
---|---|
bin | 10000010100001101011… |
… | …101100111110001001011 |
3 | 10222012001012210221101120 |
4 | 100110031131213301023 |
5 | 121332220324130011 |
6 | 2215024451250323 |
7 | 144001454404242 |
oct | 20241535476113 |
9 | 3865035727346 |
10 | 1121212333131 |
11 | 3a255a14a920 |
12 | 16136b8a99a3 |
13 | 819646a4b97 |
14 | 3c3a47ad959 |
15 | 1e272d91a06 |
hex | 1050d767c4b |
1121212333131 has 32 divisors (see below), whose sum is σ = 1636070019840. Its totient is φ = 677351808000.
The previous prime is 1121212333127. The next prime is 1121212333261. The reversal of 1121212333131 is 1313332121211.
It is not a de Polignac number, because 1121212333131 - 22 = 1121212333127 is a prime.
It is a super-2 number, since 2×11212123331312 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1121212331131) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 19277911 + ... + 19335983.
It is an arithmetic number, because the mean of its divisors is an integer number (51127188120).
Almost surely, 21121212333131 is an apocalyptic number.
1121212333131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
1121212333131 is a deficient number, since it is larger than the sum of its proper divisors (514857686709).
1121212333131 is a wasteful number, since it uses less digits than its factorization.
1121212333131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 59947.
The product of its digits is 648, while the sum is 24.
Adding to 1121212333131 its reverse (1313332121211), we get a palindrome (2434544454342).
The spelling of 1121212333131 in words is "one trillion, one hundred twenty-one billion, two hundred twelve million, three hundred thirty-three thousand, one hundred thirty-one".
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