Base | Representation |
---|---|
bin | 10000010100001101100… |
… | …000001011010100101011 |
3 | 10222012001021001222100102 |
4 | 100110031200023110223 |
5 | 121332221012044201 |
6 | 2215024513500015 |
7 | 144001463164331 |
oct | 20241540132453 |
9 | 3865037058312 |
10 | 1121213003051 |
11 | 3a255a568179 |
12 | 16136bb7160b |
13 | 8196487aa9b |
14 | 3c3a4905b51 |
15 | 1e272e7526b |
hex | 1050d80b52b |
1121213003051 has 8 divisors (see below), whose sum is σ = 1198497039264. Its totient is φ = 1046306937280.
The previous prime is 1121213003047. The next prime is 1121213003081. The reversal of 1121213003051 is 1503003121211.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1121213003051 - 22 = 1121213003047 is a prime.
It is a super-3 number, since 3×11212130030513 (a number of 37 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (1121213003081) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 594491636 + ... + 594493521.
It is an arithmetic number, because the mean of its divisors is an integer number (149812129908).
Almost surely, 21121213003051 is an apocalyptic number.
1121213003051 is a deficient number, since it is larger than the sum of its proper divisors (77284036213).
1121213003051 is a wasteful number, since it uses less digits than its factorization.
1121213003051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1188985221.
The product of its (nonzero) digits is 180, while the sum is 20.
Adding to 1121213003051 its reverse (1503003121211), we get a palindrome (2624216124262).
The spelling of 1121213003051 in words is "one trillion, one hundred twenty-one billion, two hundred thirteen million, three thousand, fifty-one".
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