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11212130034 = 232731107139193
BaseRepresentation
bin10100111000100101…
…11000011011110010
31001221101121012221100
422130102320123302
5140430301130114
65052322505230
7544563350520
oct123422703362
931841535840
1011212130034
114833a56276
12220ab05216
131098b6ab91
1478512d310
154594e2909
hex29c4b86f2

11212130034 has 192 divisors, whose sum is σ = 29285867520. Its totient is φ = 3033262080.

The previous prime is 11212130029. The next prime is 11212130107. The reversal of 11212130034 is 43003121211.

11212130034 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 11212129989 and 11212130016.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 58093842 + ... + 58094034.

It is an arithmetic number, because the mean of its divisors is an integer number (152530560).

Almost surely, 211212130034 is an apocalyptic number.

11212130034 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 11212130034, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (14642933760).

11212130034 is an abundant number, since it is smaller than the sum of its proper divisors (18073737486).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11212130034 is a wasteful number, since it uses less digits than its factorization.

11212130034 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 485 (or 482 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 11212130034 its reverse (43003121211), we get a palindrome (54215251245).

It can be divided in two parts, 11212 and 130034, that added together give a triangular number (141246 = T531).

The spelling of 11212130034 in words is "eleven billion, two hundred twelve million, one hundred thirty thousand, thirty-four".