11212130035 has 4 divisors (see below), whose sum is σ = 13454556048. Its totient is φ = 8969704024.

The previous prime is 11212130029. The next prime is 11212130107. The reversal of 11212130035 is 53003121211.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 53003121211 = 107 ⋅495356273.

It is a cyclic number.

It is not a de Polignac number, because 11212130035 - 2³¹ = 9064646387 is a prime.

It is a super-3 number, since 3×11212130035³ (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11212129994 and 11212130021.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1121212999 + ... + 1121213008.

It is an arithmetic number, because the mean of its divisors is an integer number (3363639012).

Almost surely, 2^11212130035 is an apocalyptic number.

11212130035 is a deficient number, since it is larger than the sum of its proper divisors (2242426013).

11212130035 is an equidigital number, since it uses as much as digits as its factorization.

11212130035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2242426012.

The product of its (nonzero) digits is 180, while the sum is 19.

Adding to 11212130035 its reverse (53003121211), we get a palindrome (64215251246).

The spelling of 11212130035 in words is "eleven billion, two hundred twelve million, one hundred thirty thousand, thirty-five".