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11212132121111 is a prime number
BaseRepresentation
bin1010001100101000011100…
…1001101111101000010111
31110200212110202122222020202
42203022013021233220113
52432144421310333421
635502440555051115
72235023041360655
oct243120711575027
943625422588222
1011212132121111
113633047312289
121310ba0440a9b
136343b8086acc
142aa954a27dd5
151469bec9b10b
hexa328726fa17

11212132121111 has 2 divisors, whose sum is σ = 11212132121112. Its totient is φ = 11212132121110.

The previous prime is 11212132121101. The next prime is 11212132121159. The reversal of 11212132121111 is 11112123121211.

11212132121111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a m-pointer prime, because the next prime (11212132121159) can be obtained adding 11212132121111 to its product of digits (48).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11212132121111 - 210 = 11212132120087 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11212132121101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606066060555 + 5606066060556.

It is an arithmetic number, because the mean of its divisors is an integer number (5606066060556).

Almost surely, 211212132121111 is an apocalyptic number.

11212132121111 is a deficient number, since it is larger than the sum of its proper divisors (1).

11212132121111 is an equidigital number, since it uses as much as digits as its factorization.

11212132121111 is an evil number, because the sum of its binary digits is even.

The product of its digits is 48, while the sum is 20.

Adding to 11212132121111 its reverse (11112123121211), we get a palindrome (22324255242322).

The spelling of 11212132121111 in words is "eleven trillion, two hundred twelve billion, one hundred thirty-two million, one hundred twenty-one thousand, one hundred eleven".