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11212133001 = 33737377667
BaseRepresentation
bin10100111000100101…
…11001001010001001
31001221101121101000020
422130102321022021
5140430301224001
65052322531053
7544563362256
oct123422711211
931841541006
1011212133001
114833a58523
12220ab06a89
131098b6c334
1478513042d
154594e3736
hex29c4b9289

11212133001 has 4 divisors (see below), whose sum is σ = 14949510672. Its totient is φ = 7474755332.

The previous prime is 11212132991. The next prime is 11212133017. The reversal of 11212133001 is 10033121211.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11212133001 - 25 = 11212132969 is a prime.

It is a super-2 number, since 2×112121330012 (a number of 21 digits) contains 22 as substring.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (11212133071) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1868688831 + ... + 1868688836.

It is an arithmetic number, because the mean of its divisors is an integer number (3737377668).

Almost surely, 211212133001 is an apocalyptic number.

It is an amenable number.

11212133001 is a deficient number, since it is larger than the sum of its proper divisors (3737377671).

11212133001 is an equidigital number, since it uses as much as digits as its factorization.

11212133001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3737377670.

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 11212133001 its reverse (10033121211), we get a palindrome (21245254212).

The spelling of 11212133001 in words is "eleven billion, two hundred twelve million, one hundred thirty-three thousand, one".

Divisors: 1 3 3737377667 11212133001