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112122011010122 = 256061005505061
BaseRepresentation
bin11001011111100101110000…
…101000110100010001001010
3112200222202111201122010211222
4121133211300220310101022
5104144001334304310442
61034244050224122042
732421355645506401
oct3137456050642112
9480882451563758
10112122011010122
11327a8750222833
12106a9bb6766322
134a740a25507b9
141d98a3cc5a638
15ce683ded08d2
hex65f970a3444a

112122011010122 has 4 divisors (see below), whose sum is σ = 168183016515186. Its totient is φ = 56061005505060.

The previous prime is 112122011010101. The next prime is 112122011010151. The reversal of 112122011010122 is 221010110221211.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 68669247729481 + 43452763280641 = 8286691^2 + 6591871^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 112122011010122.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28030502752529 + ... + 28030502752532.

Almost surely, 2112122011010122 is an apocalyptic number.

112122011010122 is a deficient number, since it is larger than the sum of its proper divisors (56061005505064).

112122011010122 is an equidigital number, since it uses as much as digits as its factorization.

112122011010122 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 56061005505063.

The product of its (nonzero) digits is 32, while the sum is 17.

Adding to 112122011010122 its reverse (221010110221211), we get a palindrome (333132121231333).

The spelling of 112122011010122 in words is "one hundred twelve trillion, one hundred twenty-two billion, eleven million, ten thousand, one hundred twenty-two".

Divisors: 1 2 56061005505061 112122011010122