Base | Representation |
---|---|
bin | 10000010100001101111… |
… | …011010101001011010111 |
3 | 10222012001202110121202101 |
4 | 100110031323111023113 |
5 | 121332224322340203 |
6 | 2215025330222531 |
7 | 144001610532262 |
oct | 20241573251327 |
9 | 3865052417671 |
10 | 1121220121303 |
11 | 3a256358a227 |
12 | 161372424a47 |
13 | 819661a0a79 |
14 | 3c3a5839cd9 |
15 | 1e2738ce41d |
hex | 1050ded52d7 |
1121220121303 has 2 divisors, whose sum is σ = 1121220121304. Its totient is φ = 1121220121302.
The previous prime is 1121220121249. The next prime is 1121220121319. The reversal of 1121220121303 is 3031210221211.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1121220121303 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1121220122303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560610060651 + 560610060652.
It is an arithmetic number, because the mean of its divisors is an integer number (560610060652).
Almost surely, 21121220121303 is an apocalyptic number.
1121220121303 is a deficient number, since it is larger than the sum of its proper divisors (1).
1121220121303 is an equidigital number, since it uses as much as digits as its factorization.
1121220121303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 1121220121303 its reverse (3031210221211), we get a palindrome (4152430342514).
The spelling of 1121220121303 in words is "one trillion, one hundred twenty-one billion, two hundred twenty million, one hundred twenty-one thousand, three hundred three".
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