Base | Representation |
---|---|
bin | 11001011111100101110101… |
… | …111100101101011101100111 |
3 | 112200222202201221021221120011 |
4 | 121133211311330231131213 |
5 | 104144002030112024312 |
6 | 1034244103125551051 |
7 | 32421361110036334 |
oct | 3137456574553547 |
9 | 480882657257504 |
10 | 112122100111207 |
11 | 327a879654a79a |
12 | 106aa020575487 |
13 | 4a740b7b49534 |
14 | 1d98a4aa1198b |
15 | ce6846c30da7 |
hex | 65f975f2d767 |
112122100111207 has 2 divisors, whose sum is σ = 112122100111208. Its totient is φ = 112122100111206.
The previous prime is 112122100111187. The next prime is 112122100111213. The reversal of 112122100111207 is 702111001221211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 112122100111207 - 219 = 112122099586919 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112122130111207) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56061050055603 + 56061050055604.
It is an arithmetic number, because the mean of its divisors is an integer number (56061050055604).
Almost surely, 2112122100111207 is an apocalyptic number.
112122100111207 is a deficient number, since it is larger than the sum of its proper divisors (1).
112122100111207 is an equidigital number, since it uses as much as digits as its factorization.
112122100111207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 112, while the sum is 22.
Adding to 112122100111207 its reverse (702111001221211), we get a palindrome (814233101332418).
The spelling of 112122100111207 in words is "one hundred twelve trillion, one hundred twenty-two billion, one hundred million, one hundred eleven thousand, two hundred seven".
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