Base | Representation |
---|---|
bin | 10000010100001101111… |
… | …111111010000110010111 |
3 | 10222012001211201120120201 |
4 | 100110031333322012113 |
5 | 121332230124233421 |
6 | 2215025412041331 |
7 | 144001623660253 |
oct | 20241577720627 |
9 | 3865054646521 |
10 | 1121221321111 |
11 | 3a2564229701 |
12 | 161372903247 |
13 | 81966500c08 |
14 | 3c3a5a6d263 |
15 | 1e273a69b91 |
hex | 1050dffa197 |
1121221321111 has 2 divisors, whose sum is σ = 1121221321112. Its totient is φ = 1121221321110.
The previous prime is 1121221321097. The next prime is 1121221321159. The reversal of 1121221321111 is 1111231221211.
It is a m-pointer prime, because the next prime (1121221321159) can be obtained adding 1121221321111 to its product of digits (48).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1121221321111 - 27 = 1121221320983 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1121221321711) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560610660555 + 560610660556.
It is an arithmetic number, because the mean of its divisors is an integer number (560610660556).
Almost surely, 21121221321111 is an apocalyptic number.
1121221321111 is a deficient number, since it is larger than the sum of its proper divisors (1).
1121221321111 is an equidigital number, since it uses as much as digits as its factorization.
1121221321111 is an evil number, because the sum of its binary digits is even.
The product of its digits is 48, while the sum is 19.
Adding to 1121221321111 its reverse (1111231221211), we get a palindrome (2232452542322).
The spelling of 1121221321111 in words is "one trillion, one hundred twenty-one billion, two hundred twenty-one million, three hundred twenty-one thousand, one hundred eleven".
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