Base | Representation |
---|---|
bin | 1010001100101000110001… |
… | …1001010110110110100001 |
3 | 1110200212200220012202121011 |
4 | 2203022030121112312201 |
5 | 2432200111321200001 |
6 | 35502453420500521 |
7 | 2235025160235124 |
oct | 243121431266641 |
9 | 43625626182534 |
10 | 11212220100001 |
11 | 3633091a43108 |
12 | 13110059aa741 |
13 | 63440037bb1b |
14 | 2aa9625aa3bb |
15 | 1469c7878d51 |
hex | a328c656da1 |
11212220100001 has 4 divisors (see below), whose sum is σ = 11238979575600. Its totient is φ = 11185460624404.
The previous prime is 11212220099981. The next prime is 11212220100013. The reversal of 11212220100001 is 10000102221211.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 11212220100001 - 215 = 11212220067233 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11212220100091) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13379737171 + ... + 13379738008.
It is an arithmetic number, because the mean of its divisors is an integer number (2809744893900).
Almost surely, 211212220100001 is an apocalyptic number.
It is an amenable number.
11212220100001 is a deficient number, since it is larger than the sum of its proper divisors (26759475599).
11212220100001 is an equidigital number, since it uses as much as digits as its factorization.
11212220100001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26759475598.
The product of its (nonzero) digits is 16, while the sum is 13.
Adding to 11212220100001 its reverse (10000102221211), we get a palindrome (21212322321212).
The spelling of 11212220100001 in words is "eleven trillion, two hundred twelve billion, two hundred twenty million, one hundred thousand, one".
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