Base | Representation |
---|---|
bin | 1010001100101000110001… |
… | …1001010111011000100111 |
3 | 1110200212200220012212120222 |
4 | 2203022030121113120213 |
5 | 2432200111321232213 |
6 | 35502453420514555 |
7 | 2235025160244362 |
oct | 243121431273047 |
9 | 43625626185528 |
10 | 11212220102183 |
11 | 3633091a44811 |
12 | 13110059aba5b |
13 | 63440037cb09 |
14 | 2aa9625ab0d9 |
15 | 1469c7879808 |
hex | a328c657627 |
11212220102183 has 2 divisors, whose sum is σ = 11212220102184. Its totient is φ = 11212220102182.
The previous prime is 11212220102147. The next prime is 11212220102231. The reversal of 11212220102183 is 38120102221211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11212220102183 - 242 = 6814173591079 is a prime.
It is a super-2 number, since 2×112122201021832 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11212220102123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606110051091 + 5606110051092.
It is an arithmetic number, because the mean of its divisors is an integer number (5606110051092).
Almost surely, 211212220102183 is an apocalyptic number.
11212220102183 is a deficient number, since it is larger than the sum of its proper divisors (1).
11212220102183 is an equidigital number, since it uses as much as digits as its factorization.
11212220102183 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 768, while the sum is 26.
Adding to 11212220102183 its reverse (38120102221211), we get a palindrome (49332322323394).
The spelling of 11212220102183 in words is "eleven trillion, two hundred twelve billion, two hundred twenty million, one hundred two thousand, one hundred eighty-three".
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