Base | Representation |
---|---|
bin | 11001011111100101111011… |
… | …111101111111101000111111 |
3 | 112200222202222222100021101001 |
4 | 121133211323331333220333 |
5 | 104144002231441023403 |
6 | 1034244121134431131 |
7 | 32421363444364561 |
oct | 3137457375775077 |
9 | 480882888307331 |
10 | 112122201111103 |
11 | 327a8838564487 |
12 | 106aa04a3624a7 |
13 | 4a74102a501a1 |
14 | 1d98a5a1c3331 |
15 | ce6850a31c1d |
hex | 65f97bf7fa3f |
112122201111103 has 2 divisors, whose sum is σ = 112122201111104. Its totient is φ = 112122201111102.
The previous prime is 112122201111097. The next prime is 112122201111149. The reversal of 112122201111103 is 301111102221211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 112122201111103 - 241 = 109923177855551 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112122201115103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56061100555551 + 56061100555552.
It is an arithmetic number, because the mean of its divisors is an integer number (56061100555552).
Almost surely, 2112122201111103 is an apocalyptic number.
112122201111103 is a deficient number, since it is larger than the sum of its proper divisors (1).
112122201111103 is an equidigital number, since it uses as much as digits as its factorization.
112122201111103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 19.
Adding to 112122201111103 its reverse (301111102221211), we get a palindrome (413233303332314).
The spelling of 112122201111103 in words is "one hundred twelve trillion, one hundred twenty-two billion, two hundred one million, one hundred eleven thousand, one hundred three".
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