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112122202212113 is a prime number
BaseRepresentation
bin11001011111100101111100…
…000010001100011100010001
3112200222210000001102012200012
4121133211330002030130101
5104144002232231241423
61034244121214204305
732421363456631532
oct3137457402143421
9480883001365605
10112122202212113
11327a8839146705
12106aa04a7b3695
134a74103047382
141d98a5a3cc689
15ce6850b9d078
hex65f97c08c711

112122202212113 has 2 divisors, whose sum is σ = 112122202212114. Its totient is φ = 112122202212112.

The previous prime is 112122202212089. The next prime is 112122202212161. The reversal of 112122202212113 is 311212202221211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 104721800156689 + 7400402055424 = 10233367^2 + 2720368^2 .

It is a cyclic number.

It is not a de Polignac number, because 112122202212113 - 212 = 112122202208017 is a prime.

It is not a weakly prime, because it can be changed into another prime (112122202212613) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56061101106056 + 56061101106057.

It is an arithmetic number, because the mean of its divisors is an integer number (56061101106057).

Almost surely, 2112122202212113 is an apocalyptic number.

It is an amenable number.

112122202212113 is a deficient number, since it is larger than the sum of its proper divisors (1).

112122202212113 is an equidigital number, since it uses as much as digits as its factorization.

112122202212113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 384, while the sum is 23.

Adding to 112122202212113 its reverse (311212202221211), we get a palindrome (423334404433324).

The spelling of 112122202212113 in words is "one hundred twelve trillion, one hundred twenty-two billion, two hundred two million, two hundred twelve thousand, one hundred thirteen".