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11212300112113 = 62483179445611
BaseRepresentation
bin1010001100101001000100…
…1010100101000011110001
31110200212220110202210120201
42203022101022211003301
52432200242312041423
635502505355435201
72235030151311442
oct243122112450361
943625813683521
1011212300112113
113633123122421
121311028755b01
13634413b14879
142aa96d0772c9
151469ce8d12ad
hexa32912a50f1

11212300112113 has 4 divisors (see below), whose sum is σ = 11212479620208. Its totient is φ = 11212120604020.

The previous prime is 11212300112107. The next prime is 11212300112137. The reversal of 11212300112113 is 31121100321211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11212300112113 - 29 = 11212300111601 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11212300112173) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 89660323 + ... + 89785288.

It is an arithmetic number, because the mean of its divisors is an integer number (2803119905052).

Almost surely, 211212300112113 is an apocalyptic number.

It is an amenable number.

11212300112113 is a deficient number, since it is larger than the sum of its proper divisors (179508095).

11212300112113 is an equidigital number, since it uses as much as digits as its factorization.

11212300112113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 179508094.

The product of its (nonzero) digits is 72, while the sum is 19.

Adding to 11212300112113 its reverse (31121100321211), we get a palindrome (42333400433324).

The spelling of 11212300112113 in words is "eleven trillion, two hundred twelve billion, three hundred million, one hundred twelve thousand, one hundred thirteen".

Divisors: 1 62483 179445611 11212300112113