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11212313443 = 88112726803
BaseRepresentation
bin10100111000100111…
…00101001101100011
31001221101221112112021
422130103211031203
5140430323012233
65052330442311
7544565043322
oct123423451543
931841845467
1011212313443
114834071051
12220ab93397
131098c034c6
1478517a0b9
1545952be2d
hex29c4e5363

11212313443 has 4 divisors (see below), whose sum is σ = 11225041128. Its totient is φ = 11199585760.

The previous prime is 11212313393. The next prime is 11212313473. The reversal of 11212313443 is 34431321211.

11212313443 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11212313443 - 29 = 11212312931 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11212313473) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6362521 + ... + 6364282.

It is an arithmetic number, because the mean of its divisors is an integer number (2806260282).

Almost surely, 211212313443 is an apocalyptic number.

11212313443 is a deficient number, since it is larger than the sum of its proper divisors (12727685).

11212313443 is an equidigital number, since it uses as much as digits as its factorization.

11212313443 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12727684.

The product of its digits is 1728, while the sum is 25.

Adding to 11212313443 its reverse (34431321211), we get a palindrome (45643634654).

The spelling of 11212313443 in words is "eleven billion, two hundred twelve million, three hundred thirteen thousand, four hundred forty-three".

Divisors: 1 881 12726803 11212313443