Base | Representation |
---|---|
bin | 10000010100001110101… |
… | …101101101111110110011 |
3 | 10222012002200022200211001 |
4 | 100110032231231332303 |
5 | 121332241213030344 |
6 | 2215030521302431 |
7 | 144002131025011 |
oct | 20241655557663 |
9 | 3865080280731 |
10 | 1121233330099 |
11 | 3a256aa91193 |
12 | 161376934a17 |
13 | 81968b4701c |
14 | 3c3a74b78b1 |
15 | 1e274b3ced4 |
hex | 1050eb6dfb3 |
1121233330099 has 2 divisors, whose sum is σ = 1121233330100. Its totient is φ = 1121233330098.
The previous prime is 1121233330093. The next prime is 1121233330219. The reversal of 1121233330099 is 9900333321211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1121233330099 - 225 = 1121199775667 is a prime.
It is a super-3 number, since 3×11212333300993 (a number of 37 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (1121233330093) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 560616665049 + 560616665050.
It is an arithmetic number, because the mean of its divisors is an integer number (560616665050).
Almost surely, 21121233330099 is an apocalyptic number.
1121233330099 is a deficient number, since it is larger than the sum of its proper divisors (1).
1121233330099 is an equidigital number, since it uses as much as digits as its factorization.
1121233330099 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 26244, while the sum is 37.
The spelling of 1121233330099 in words is "one trillion, one hundred twenty-one billion, two hundred thirty-three million, three hundred thirty thousand, ninety-nine".
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