Base | Representation |
---|---|
bin | 11001011111100111101111… |
… | …001111010100010101011011 |
3 | 112200222221222202100122022200 |
4 | 121133213233033110111123 |
5 | 104144020212032012110 |
6 | 1034245041101221243 |
7 | 32421462406423431 |
oct | 3137475717242533 |
9 | 480887882318280 |
10 | 112124135032155 |
11 | 327a9640178a44 |
12 | 106aa4a9b61823 |
13 | 4a743505cc67c |
14 | 1d98ba0d9ad51 |
15 | ce69156e06c0 |
hex | 65f9ef3d455b |
112124135032155 has 24 divisors (see below), whose sum is σ = 197010808957248. Its totient is φ = 58980366919296.
The previous prime is 112124135032109. The next prime is 112124135032193. The reversal of 112124135032155 is 551230531421211.
112124135032155 is a `hidden beast` number, since 1 + 1 + 2 + 12 + 413 + 50 + 32 + 155 = 666.
It is not a de Polignac number, because 112124135032155 - 213 = 112124135023963 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 17066075107 + ... + 17066081676.
It is an arithmetic number, because the mean of its divisors is an integer number (8208783706552).
Almost surely, 2112124135032155 is an apocalyptic number.
112124135032155 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
112124135032155 is a deficient number, since it is larger than the sum of its proper divisors (84886673925093).
112124135032155 is a wasteful number, since it uses less digits than its factorization.
112124135032155 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 34132156867 (or 34132156864 counting only the distinct ones).
The product of its (nonzero) digits is 36000, while the sum is 36.
Adding to 112124135032155 its reverse (551230531421211), we get a palindrome (663354666453366).
The spelling of 112124135032155 in words is "one hundred twelve trillion, one hundred twenty-four billion, one hundred thirty-five million, thirty-two thousand, one hundred fifty-five".
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