Base | Representation |
---|---|
bin | 11001011111100111101111… |
… | …001111010100010111101111 |
3 | 112200222221222202100122112011 |
4 | 121133213233033110113233 |
5 | 104144020212032013203 |
6 | 1034245041101222051 |
7 | 32421462406424032 |
oct | 3137475717242757 |
9 | 480887882318464 |
10 | 112124135032303 |
11 | 327a9640179069 |
12 | 106aa4a9b61927 |
13 | 4a743505cc764 |
14 | 1d98ba0d9b019 |
15 | ce69156e076d |
hex | 65f9ef3d45ef |
112124135032303 has 2 divisors, whose sum is σ = 112124135032304. Its totient is φ = 112124135032302.
The previous prime is 112124135032291. The next prime is 112124135032313. The reversal of 112124135032303 is 303230531421211.
It is a strong prime.
It is an emirp because it is prime and its reverse (303230531421211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 112124135032303 - 245 = 76939762943471 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112124135032313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56062067516151 + 56062067516152.
It is an arithmetic number, because the mean of its divisors is an integer number (56062067516152).
Almost surely, 2112124135032303 is an apocalyptic number.
112124135032303 is a deficient number, since it is larger than the sum of its proper divisors (1).
112124135032303 is an equidigital number, since it uses as much as digits as its factorization.
112124135032303 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12960, while the sum is 31.
Adding to 112124135032303 its reverse (303230531421211), we get a palindrome (415354666453514).
The spelling of 112124135032303 in words is "one hundred twelve trillion, one hundred twenty-four billion, one hundred thirty-five million, thirty-two thousand, three hundred three".
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