Base | Representation |
---|---|
bin | 1010001100101001110111… |
… | …0110110011010100011101 |
3 | 1110200220110022102020000012 |
4 | 2203022131312303110131 |
5 | 2432201211314001303 |
6 | 35502542443213005 |
7 | 2235035345144516 |
oct | 243123566632435 |
9 | 43626408366005 |
10 | 11212513031453 |
11 | 3633222329918 |
12 | 1311087b17165 |
13 | 634448c73446 |
14 | 2aa98d45da0d |
15 | 1469e343d5d8 |
hex | a329ddb351d |
11212513031453 has 2 divisors, whose sum is σ = 11212513031454. Its totient is φ = 11212513031452.
The previous prime is 11212513031327. The next prime is 11212513031459. The reversal of 11212513031453 is 35413031521211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11031784316569 + 180728714884 = 3321413^2 + 425122^2 .
It is a cyclic number.
It is not a de Polignac number, because 11212513031453 - 28 = 11212513031197 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11212513031459) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606256515726 + 5606256515727.
It is an arithmetic number, because the mean of its divisors is an integer number (5606256515727).
Almost surely, 211212513031453 is an apocalyptic number.
It is an amenable number.
11212513031453 is a deficient number, since it is larger than the sum of its proper divisors (1).
11212513031453 is an equidigital number, since it uses as much as digits as its factorization.
11212513031453 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10800, while the sum is 32.
Adding to 11212513031453 its reverse (35413031521211), we get a palindrome (46625544552664).
The spelling of 11212513031453 in words is "eleven trillion, two hundred twelve billion, five hundred thirteen million, thirty-one thousand, four hundred fifty-three".
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