Base | Representation |
---|---|
bin | 10100111000101000… |
… | …11101010101101101 |
3 | 1001221102101012220000 |
4 | 22130110131111231 |
5 | 140430402341331 |
6 | 5052335414513 |
7 | 544600021506 |
oct | 123424352555 |
9 | 31842335800 |
10 | 11212543341 |
11 | 483420884a |
12 | 220b084439 |
13 | 1098c8403c |
14 | 7851d9bad |
15 | 4595750e6 |
hex | 29c51d56d |
11212543341 has 20 divisors (see below), whose sum is σ = 17734874652. Its totient is φ = 7035320448.
The previous prime is 11212543301. The next prime is 11212543367. The reversal of 11212543341 is 14334521211.
11212543341 is a `hidden beast` number, since 11 + 212 + 5 + 433 + 4 + 1 = 666.
It can be written as a sum of positive squares in 2 ways, for example, as 8645094441 + 2567448900 = 92979^2 + 50670^2 .
It is not a de Polignac number, because 11212543341 - 29 = 11212542829 is a prime.
It is a super-2 number, since 2×112125433412 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11212543301) by changing a digit.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 4069990 + ... + 4072743.
Almost surely, 211212543341 is an apocalyptic number.
It is an amenable number.
11212543341 is a deficient number, since it is larger than the sum of its proper divisors (6522331311).
11212543341 is an equidigital number, since it uses as much as digits as its factorization.
11212543341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8142762 (or 8142753 counting only the distinct ones).
The product of its digits is 2880, while the sum is 27.
The spelling of 11212543341 in words is "eleven billion, two hundred twelve million, five hundred forty-three thousand, three hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •