Base | Representation |
---|---|
bin | 10100111000101100… |
… | …01100111000110011 |
3 | 1001221110020102122022 |
4 | 22130112030320303 |
5 | 140431012001433 |
6 | 5052353302055 |
7 | 544603633544 |
oct | 123426147063 |
9 | 31843212568 |
10 | 11213000243 |
11 | 48344a0055 |
12 | 220b26492b |
13 | 10990b3cb3 |
14 | 7852b84cb |
15 | 459615698 |
hex | 29c58ce33 |
11213000243 has 2 divisors, whose sum is σ = 11213000244. Its totient is φ = 11213000242.
The previous prime is 11213000213. The next prime is 11213000261. The reversal of 11213000243 is 34200031211.
11213000243 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (34200031211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11213000243 - 26 = 11213000179 is a prime.
It is not a weakly prime, because it can be changed into another prime (11213000213) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606500121 + 5606500122.
It is an arithmetic number, because the mean of its divisors is an integer number (5606500122).
Almost surely, 211213000243 is an apocalyptic number.
11213000243 is a deficient number, since it is larger than the sum of its proper divisors (1).
11213000243 is an equidigital number, since it uses as much as digits as its factorization.
11213000243 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 11213000243 its reverse (34200031211), we get a palindrome (45413031454).
The spelling of 11213000243 in words is "eleven billion, two hundred thirteen million, two hundred forty-three", and thus it is an aban number.
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