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112130011303 is a prime number
BaseRepresentation
bin110100001101101111…
…0000011000010100111
3101201102112101202120121
41220123132003002213
53314120240330203
6123302315142411
711046454240642
oct1503336030247
9351375352517
10112130011303
1143610517132
1219894144a07
13a75c894c1b
1455da042a59
152db40dc0bd
hex1a1b7830a7

112130011303 has 2 divisors, whose sum is σ = 112130011304. Its totient is φ = 112130011302.

The previous prime is 112130011291. The next prime is 112130011307. The reversal of 112130011303 is 303110031211.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 112130011303 - 233 = 103540076711 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (112130011307) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56065005651 + 56065005652.

It is an arithmetic number, because the mean of its divisors is an integer number (56065005652).

Almost surely, 2112130011303 is an apocalyptic number.

112130011303 is a deficient number, since it is larger than the sum of its proper divisors (1).

112130011303 is an equidigital number, since it uses as much as digits as its factorization.

112130011303 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 112130011303 its reverse (303110031211), we get a palindrome (415240042514).

The spelling of 112130011303 in words is "one hundred twelve billion, one hundred thirty million, eleven thousand, three hundred three".