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11213005035 = 351237760397
BaseRepresentation
bin10100111000101100…
…01110000011101011
31001221110020200012210
422130112032003223
5140431012130120
65052353340203
7544603653531
oct123426160353
931843220183
1011213005035
1148344a3711
12220b267663
1310990b622b
147852ba151
15459616ce0
hex29c58e0eb

11213005035 has 16 divisors (see below), whose sum is σ = 17942554656. Its totient is φ = 5979687168.

The previous prime is 11213005031. The next prime is 11213005051. The reversal of 11213005035 is 53050031211.

11213005035 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 11213005035 - 22 = 11213005031 is a prime.

It is not an unprimeable number, because it can be changed into a prime (11213005031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 155457 + ... + 215853.

It is an arithmetic number, because the mean of its divisors is an integer number (1121409666).

Almost surely, 211213005035 is an apocalyptic number.

11213005035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

11213005035 is a deficient number, since it is larger than the sum of its proper divisors (6729549621).

11213005035 is a wasteful number, since it uses less digits than its factorization.

11213005035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 72782.

The product of its (nonzero) digits is 450, while the sum is 21.

Adding to 11213005035 its reverse (53050031211), we get a palindrome (64263036246).

The spelling of 11213005035 in words is "eleven billion, two hundred thirteen million, five thousand, thirty-five".

Divisors: 1 3 5 15 12377 37131 60397 61885 181191 185655 301985 905955 747533669 2242601007 3737668345 11213005035