11213010033 has 4 divisors (see below), whose sum is σ = 14950680048. Its totient is φ = 7475340020.

The previous prime is 11213010019. The next prime is 11213010041. The reversal of 11213010033 is 33001031211.

11213010033 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11213010033 - 2⁸ = 11213009777 is a prime.

It is a super-2 number, since 2×11213010033² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11213009994 and 11213010021.

It is not an unprimeable number, because it can be changed into a prime (11213010013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1868835003 + ... + 1868835008.

It is an arithmetic number, because the mean of its divisors is an integer number (3737670012).

Almost surely, 2^11213010033 is an apocalyptic number.

It is an amenable number.

11213010033 is a deficient number, since it is larger than the sum of its proper divisors (3737670015).

11213010033 is an equidigital number, since it uses as much as digits as its factorization.

11213010033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3737670014.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 11213010033 its reverse (33001031211), we get a palindrome (44214041244).

The spelling of 11213010033 in words is "eleven billion, two hundred thirteen million, ten thousand, thirty-three".