Base | Representation |
---|---|
bin | 10100111000101100… |
… | …01111100101100111 |
3 | 1001221110020222210221 |
4 | 22130112033211213 |
5 | 140431012330203 |
6 | 5052353425211 |
7 | 544604011024 |
oct | 123426174547 |
9 | 31843228727 |
10 | 11213011303 |
11 | 48344a839a |
12 | 220b26b207 |
13 | 10990b9040 |
14 | 7852bc54b |
15 | 459618abd |
hex | 29c58f967 |
11213011303 has 16 divisors (see below), whose sum is σ = 12384985536. Its totient is φ = 10087833600.
The previous prime is 11213011297. The next prime is 11213011319. The reversal of 11213011303 is 30311031211.
It is not a de Polignac number, because 11213011303 - 29 = 11213010791 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11213011363) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 50151 + ... + 157927.
It is an arithmetic number, because the mean of its divisors is an integer number (774061596).
Almost surely, 211213011303 is an apocalyptic number.
11213011303 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
11213011303 is a deficient number, since it is larger than the sum of its proper divisors (1171974233).
11213011303 is a wasteful number, since it uses less digits than its factorization.
11213011303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 107994.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 11213011303 its reverse (30311031211), we get a palindrome (41524042514).
The spelling of 11213011303 in words is "eleven billion, two hundred thirteen million, eleven thousand, three hundred three".
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