Base | Representation |
---|---|
bin | 11001011111101101010011… |
… | …100011111000000100011100 |
3 | 112201000112102101011110212100 |
4 | 121133231103203320010130 |
5 | 104144114432424012200 |
6 | 1034251510212205100 |
7 | 32422063506306615 |
oct | 3137552343700434 |
9 | 481015371143770 |
10 | 112130113110300 |
11 | 3280112869659a |
12 | 106ab698009790 |
13 | 4a74a93c9130c |
14 | 1d991aad00c0c |
15 | ce6b65447d00 |
hex | 65fb538f811c |
112130113110300 has 432 divisors, whose sum is σ = 360168861780000. Its totient is φ = 29169096744960.
The previous prime is 112130113110221. The next prime is 112130113110361. The reversal of 112130113110300 is 3011311031211.
112130113110300 is a `hidden beast` number, since 1 + 1 + 21 + 30 + 1 + 1 + 311 + 0 + 300 = 666.
It is a super-2 number, since 2×1121301131103002 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 8932528824 + ... + 8932541376.
Almost surely, 2112130113110300 is an apocalyptic number.
112130113110300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 112130113110300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (180084430890000).
112130113110300 is an abundant number, since it is smaller than the sum of its proper divisors (248038748669700).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
112130113110300 is a wasteful number, since it uses less digits than its factorization.
112130113110300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13910 (or 13900 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 18.
Adding to 112130113110300 its reverse (3011311031211), we get a palindrome (115141424141511).
The spelling of 112130113110300 in words is "one hundred twelve trillion, one hundred thirty billion, one hundred thirteen million, one hundred ten thousand, three hundred".
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