Search a number
-
+
112130220021 = 337376740007
BaseRepresentation
bin110100001101101111…
…0110101111111110101
3101201102112210100212220
41220123132311333311
53314120314020041
6123302323432553
711046456100311
oct1503336657765
9351375710786
10112130220021
1143610649a26
1219894225759
13a75c938c21
1455da098b41
152db412dd66
hex1a1b7b5ff5

112130220021 has 4 divisors (see below), whose sum is σ = 149506960032. Its totient is φ = 74753480012.

The previous prime is 112130219989. The next prime is 112130220071. The reversal of 112130220021 is 120022031211.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 112130220021 - 25 = 112130219989 is a prime.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (112130220071) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18688370001 + ... + 18688370006.

It is an arithmetic number, because the mean of its divisors is an integer number (37376740008).

Almost surely, 2112130220021 is an apocalyptic number.

It is an amenable number.

112130220021 is a deficient number, since it is larger than the sum of its proper divisors (37376740011).

112130220021 is an equidigital number, since it uses as much as digits as its factorization.

112130220021 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 37376740010.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 112130220021 its reverse (120022031211), we get a palindrome (232152251232).

The spelling of 112130220021 in words is "one hundred twelve billion, one hundred thirty million, two hundred twenty thousand, twenty-one".

Divisors: 1 3 37376740007 112130220021