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11213100133333 = 76121261700939
BaseRepresentation
bin1010001100101100000011…
…0110011010101111010101
31110200221222020011002101021
42203023000312122233111
52432203412113231313
635503121015001141
72235056034344020
oct243130066325725
943627866132337
1011213100133333
1136334a377818a
1213112106691b1
136345107a42c7
142aaa0740a1b7
15146a29c5e78d
hexa32c0d9abd5

11213100133333 has 8 divisors (see below), whose sum is σ = 12817065237440. Its totient is φ = 9609658443360.

The previous prime is 11213100133171. The next prime is 11213100133379. The reversal of 11213100133333 is 33333100131211.

11213100133333 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11213100133333 - 29 = 11213100132821 is a prime.

It is a super-2 number, since 2×112131001333332 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11213100133298 and 11213100133307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11213100133393) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 130807623 + ... + 130893316.

It is an arithmetic number, because the mean of its divisors is an integer number (1602133154680).

Almost surely, 211213100133333 is an apocalyptic number.

It is an amenable number.

11213100133333 is a deficient number, since it is larger than the sum of its proper divisors (1603965104107).

11213100133333 is an equidigital number, since it uses as much as digits as its factorization.

11213100133333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 261707067.

The product of its (nonzero) digits is 1458, while the sum is 25.

Adding to 11213100133333 its reverse (33333100131211), we get a palindrome (44546200264544).

The spelling of 11213100133333 in words is "eleven trillion, two hundred thirteen billion, one hundred million, one hundred thirty-three thousand, three hundred thirty-three".

Divisors: 1 7 6121 42847 261700939 1831906573 1601871447619 11213100133333