Base | Representation |
---|---|
bin | 10100111000101101… |
… | …00110000000011011 |
3 | 1001221110102122202222 |
4 | 22130112212000123 |
5 | 140431023300011 |
6 | 5052355414255 |
7 | 544604542526 |
oct | 123426460033 |
9 | 31843378688 |
10 | 11213103131 |
11 | 483456038a |
12 | 220b2b438b |
13 | 109911ba89 |
14 | 785303bbd |
15 | 459635ddb |
hex | 29c5a601b |
11213103131 has 2 divisors, whose sum is σ = 11213103132. Its totient is φ = 11213103130.
The previous prime is 11213103127. The next prime is 11213103149. The reversal of 11213103131 is 13130131211.
It is a weak prime.
It is an emirp because it is prime and its reverse (13130131211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11213103131 - 22 = 11213103127 is a prime.
It is a super-2 number, since 2×112131031312 (a number of 21 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (11213103101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606551565 + 5606551566.
It is an arithmetic number, because the mean of its divisors is an integer number (5606551566).
Almost surely, 211213103131 is an apocalyptic number.
11213103131 is a deficient number, since it is larger than the sum of its proper divisors (1).
11213103131 is an equidigital number, since it uses as much as digits as its factorization.
11213103131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 11213103131 its reverse (13130131211), we get a palindrome (24343234342).
The spelling of 11213103131 in words is "eleven billion, two hundred thirteen million, one hundred three thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.079 sec. • engine limits •