112131141251 has 4 divisors (see below), whose sum is σ = 112314063792. Its totient is φ = 111948218712.

The previous prime is 112131141229. The next prime is 112131141257. The reversal of 112131141251 is 152141131211.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 152141131211 = 131 ⋅1161382681.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-112131141251 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (112131141257) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 91460351 + ... + 91461576.

It is an arithmetic number, because the mean of its divisors is an integer number (28078515948).

Almost surely, 2^112131141251 is an apocalyptic number.

112131141251 is a deficient number, since it is larger than the sum of its proper divisors (182922541).

112131141251 is an equidigital number, since it uses as much as digits as its factorization.

112131141251 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 182922540.

The product of its digits is 240, while the sum is 23.

Adding to 112131141251 its reverse (152141131211), we get a palindrome (264272272462).

The spelling of 112131141251 in words is "one hundred twelve billion, one hundred thirty-one million, one hundred forty-one thousand, two hundred fifty-one".