Base | Representation |
---|---|
bin | 1010001100101100001000… |
… | …1010010101010011111111 |
3 | 1110200222000202112200210001 |
4 | 2203023002022111103333 |
5 | 2432203433231144244 |
6 | 35503123122255131 |
7 | 2235056422333522 |
oct | 243130212252377 |
9 | 43628022480701 |
10 | 11213122131199 |
11 | 363350513253a |
12 | 1311217ab74a7 |
13 | 634515206bb1 |
14 | 2aaa0a2d4bb9 |
15 | 146a2bb575d4 |
hex | a32c22954ff |
11213122131199 has 2 divisors, whose sum is σ = 11213122131200. Its totient is φ = 11213122131198.
The previous prime is 11213122131193. The next prime is 11213122131221. The reversal of 11213122131199 is 99113122131211.
11213122131199 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11213122131199 - 233 = 11204532196607 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11213122131193) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606561065599 + 5606561065600.
It is an arithmetic number, because the mean of its divisors is an integer number (5606561065600).
Almost surely, 211213122131199 is an apocalyptic number.
11213122131199 is a deficient number, since it is larger than the sum of its proper divisors (1).
11213122131199 is an equidigital number, since it uses as much as digits as its factorization.
11213122131199 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5832, while the sum is 37.
The spelling of 11213122131199 in words is "eleven trillion, two hundred thirteen billion, one hundred twenty-two million, one hundred thirty-one thousand, one hundred ninety-nine".
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