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11213123113 is a prime number
BaseRepresentation
bin10100111000101101…
…01010111000101001
31001221110110200012001
422130112222320221
5140431024414423
65052400051001
7544604655013
oct123426527051
931843420161
1011213123113
1148345743a5
12220b303a61
131099127bba
1478530b1b3
1545963bcad
hex29c5aae29

11213123113 has 2 divisors, whose sum is σ = 11213123114. Its totient is φ = 11213123112.

The previous prime is 11213123071. The next prime is 11213123167. The reversal of 11213123113 is 31132131211.

11213123113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11123499024 + 89624089 = 105468^2 + 9467^2 .

It is an emirp because it is prime and its reverse (31132131211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11213123113 - 29 = 11213122601 is a prime.

It is not a weakly prime, because it can be changed into another prime (11213123213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606561556 + 5606561557.

It is an arithmetic number, because the mean of its divisors is an integer number (5606561557).

Almost surely, 211213123113 is an apocalyptic number.

It is an amenable number.

11213123113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11213123113 is an equidigital number, since it uses as much as digits as its factorization.

11213123113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 108, while the sum is 19.

Adding to 11213123113 its reverse (31132131211), we get a palindrome (42345254324).

The spelling of 11213123113 in words is "eleven billion, two hundred thirteen million, one hundred twenty-three thousand, one hundred thirteen".