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112131420133 = 891667755791
BaseRepresentation
bin110100001101110001…
…1011010111111100101
3101201102122001100010111
41220123203122333211
53314121120421013
6123302405253021
711046502226215
oct1503343327745
9351378040114
10112131420133
1143611299657
1219894704171
13a75cc69255
1455da2cc245
152db42b973d
hex1a1b8dafe5

112131420133 has 8 divisors (see below), whose sum is σ = 113459495040. Its totient is φ = 110804860320.

The previous prime is 112131420131. The next prime is 112131420139. The reversal of 112131420133 is 331024131211.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 112131420133 - 21 = 112131420131 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (112131420131) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 229533 + ... + 526258.

It is an arithmetic number, because the mean of its divisors is an integer number (14182436880).

Almost surely, 2112131420133 is an apocalyptic number.

It is an amenable number.

112131420133 is a deficient number, since it is larger than the sum of its proper divisors (1328074907).

112131420133 is an equidigital number, since it uses as much as digits as its factorization.

112131420133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 757547.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 112131420133 its reverse (331024131211), we get a palindrome (443155551344).

The spelling of 112131420133 in words is "one hundred twelve billion, one hundred thirty-one million, four hundred twenty thousand, one hundred thirty-three".

Divisors: 1 89 1667 148363 755791 67265399 1259903597 112131420133