Base | Representation |
---|---|
bin | 11001011111101110101001… |
… | …010101100111100111111111 |
3 | 112201000200010200002111022222 |
4 | 121133232221111213213333 |
5 | 104144130404331313003 |
6 | 1034252305101155555 |
7 | 32422144252424024 |
oct | 3137565125474777 |
9 | 481020120074288 |
10 | 112131552213503 |
11 | 328017a6a63089 |
12 | 106aba19b5bbbb |
13 | 4a74c63181384 |
14 | 1d992a60b154b |
15 | ce6beb963c38 |
hex | 65fba95679ff |
112131552213503 has 2 divisors, whose sum is σ = 112131552213504. Its totient is φ = 112131552213502.
The previous prime is 112131552213491. The next prime is 112131552213511. The reversal of 112131552213503 is 305312255131211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 112131552213503 - 210 = 112131552212479 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112131552213203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56065776106751 + 56065776106752.
It is an arithmetic number, because the mean of its divisors is an integer number (56065776106752).
Almost surely, 2112131552213503 is an apocalyptic number.
112131552213503 is a deficient number, since it is larger than the sum of its proper divisors (1).
112131552213503 is an equidigital number, since it uses as much as digits as its factorization.
112131552213503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27000, while the sum is 35.
The spelling of 112131552213503 in words is "one hundred twelve trillion, one hundred thirty-one billion, five hundred fifty-two million, two hundred thirteen thousand, five hundred three".
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