Base | Representation |
---|---|
bin | 10100111000101101… |
… | …11101111101111001 |
3 | 1001221110121122101212 |
4 | 22130112331331321 |
5 | 140431034420043 |
6 | 5052401452505 |
7 | 544605431621 |
oct | 123426757571 |
9 | 31843548355 |
10 | 11213201273 |
11 | 483461809a |
12 | 220b341135 |
13 | 1099154651 |
14 | 78532b881 |
15 | 459655018 |
hex | 29c5bdf79 |
11213201273 has 2 divisors, whose sum is σ = 11213201274. Its totient is φ = 11213201272.
The previous prime is 11213201269. The next prime is 11213201287. The reversal of 11213201273 is 37210231211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10562083984 + 651117289 = 102772^2 + 25517^2 .
It is an emirp because it is prime and its reverse (37210231211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11213201273 - 22 = 11213201269 is a prime.
It is not a weakly prime, because it can be changed into another prime (11213201773) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606600636 + 5606600637.
It is an arithmetic number, because the mean of its divisors is an integer number (5606600637).
Almost surely, 211213201273 is an apocalyptic number.
It is an amenable number.
11213201273 is a deficient number, since it is larger than the sum of its proper divisors (1).
11213201273 is an equidigital number, since it uses as much as digits as its factorization.
11213201273 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504, while the sum is 23.
Adding to 11213201273 its reverse (37210231211), we get a palindrome (48423432484).
The spelling of 11213201273 in words is "eleven billion, two hundred thirteen million, two hundred one thousand, two hundred seventy-three".
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