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11213211143 is a prime number
BaseRepresentation
bin10100111000101110…
…00000011000000111
31001221110122010221102
422130113000120013
5140431040224033
65052402010315
7544605502451
oct123427003007
931843563842
1011213211143
114834624552
12220b34699b
131099158ca4
147853312d1
15459657de8
hex29c5c0607

11213211143 has 2 divisors, whose sum is σ = 11213211144. Its totient is φ = 11213211142.

The previous prime is 11213211109. The next prime is 11213211277. The reversal of 11213211143 is 34111231211.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11213211143 - 216 = 11213145607 is a prime.

It is a super-2 number, since 2×112132111432 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11213211103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606605571 + 5606605572.

It is an arithmetic number, because the mean of its divisors is an integer number (5606605572).

Almost surely, 211213211143 is an apocalyptic number.

11213211143 is a deficient number, since it is larger than the sum of its proper divisors (1).

11213211143 is an equidigital number, since it uses as much as digits as its factorization.

11213211143 is an evil number, because the sum of its binary digits is even.

The product of its digits is 144, while the sum is 20.

Adding to 11213211143 its reverse (34111231211), we get a palindrome (45324442354).

The spelling of 11213211143 in words is "eleven billion, two hundred thirteen million, two hundred eleven thousand, one hundred forty-three".