Base | Representation |
---|---|
bin | 1010001100101100011101… |
… | …1110100110110111110111 |
3 | 1110200222020222101120101122 |
4 | 2203023013132212313313 |
5 | 2432204124100111322 |
6 | 35503140030214155 |
7 | 2235061554460442 |
oct | 243130736466767 |
9 | 43628228346348 |
10 | 11213211332087 |
11 | 3633550518486 |
12 | 131124195435b |
13 | 63452a83919b |
14 | 2aaa180b4659 |
15 | 146a348c7442 |
hex | a32c77a6df7 |
11213211332087 has 2 divisors, whose sum is σ = 11213211332088. Its totient is φ = 11213211332086.
The previous prime is 11213211332069. The next prime is 11213211332119. The reversal of 11213211332087 is 78023311231211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11213211332087 - 212 = 11213211327991 is a prime.
It is a super-2 number, since 2×112132113320872 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11213211302087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606605666043 + 5606605666044.
It is an arithmetic number, because the mean of its divisors is an integer number (5606605666044).
Almost surely, 211213211332087 is an apocalyptic number.
11213211332087 is a deficient number, since it is larger than the sum of its proper divisors (1).
11213211332087 is an equidigital number, since it uses as much as digits as its factorization.
11213211332087 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12096, while the sum is 35.
Adding to 11213211332087 its reverse (78023311231211), we get a palindrome (89236522563298).
The spelling of 11213211332087 in words is "eleven trillion, two hundred thirteen billion, two hundred eleven million, three hundred thirty-two thousand, eighty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.078 sec. • engine limits •