Base | Representation |
---|---|
bin | 1010001100101100110101… |
… | …1011010000001101110001 |
3 | 1110200222111221011010101111 |
4 | 2203023031123100031301 |
5 | 2432204330121204040 |
6 | 35503153553033321 |
7 | 2235064205563165 |
oct | 243131533201561 |
9 | 43628457133344 |
10 | 11213311116145 |
11 | 36335a1881746 |
12 | 131126b255841 |
13 | 6345454055c8 |
14 | 2aaa2744aca5 |
15 | 146a3d537dea |
hex | a32cd6d0371 |
11213311116145 has 32 divisors (see below), whose sum is σ = 13606214049792. Its totient is φ = 8870749228992.
The previous prime is 11213311116127. The next prime is 11213311116151. The reversal of 11213311116145 is 54161111331211.
It is a cyclic number.
It is not a de Polignac number, because 11213311116145 - 213 = 11213311107953 is a prime.
It is a super-2 number, since 2×112133111161452 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1376368962 + ... + 1376377108.
It is an arithmetic number, because the mean of its divisors is an integer number (425194189056).
Almost surely, 211213311116145 is an apocalyptic number.
It is an amenable number.
11213311116145 is a deficient number, since it is larger than the sum of its proper divisors (2392902933647).
11213311116145 is a wasteful number, since it uses less digits than its factorization.
11213311116145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11781.
The product of its digits is 2160, while the sum is 31.
Adding to 11213311116145 its reverse (54161111331211), we get a palindrome (65374422447356).
The spelling of 11213311116145 in words is "eleven trillion, two hundred thirteen billion, three hundred eleven million, one hundred sixteen thousand, one hundred forty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •