Base | Representation |
---|---|
bin | 10000010100010100100… |
… | …011000110011100111101 |
3 | 10222012100111111111212020 |
4 | 100110110203012130331 |
5 | 121332441242210140 |
6 | 2215044335230353 |
7 | 144004430010204 |
oct | 20242443063475 |
9 | 3865314444766 |
10 | 1121331210045 |
11 | 3a2610264902 |
12 | 1613a36783b9 |
13 | 819831c7857 |
14 | 3c3b64b623b |
15 | 1e27d5246d0 |
hex | 105148c673d |
1121331210045 has 16 divisors (see below), whose sum is σ = 1810897508160. Its totient is φ = 592454121344.
The previous prime is 1121331210007. The next prime is 1121331210073. The reversal of 1121331210045 is 5400121331211.
It is a cyclic number.
It is not a de Polignac number, because 1121331210045 - 212 = 1121331205949 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1121331209997 and 1121331210024.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 349322760 + ... + 349325969.
It is an arithmetic number, because the mean of its divisors is an integer number (113181094260).
Almost surely, 21121331210045 is an apocalyptic number.
1121331210045 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
1121331210045 is a deficient number, since it is larger than the sum of its proper divisors (689566298115).
1121331210045 is a wasteful number, since it uses less digits than its factorization.
1121331210045 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 698648844.
The product of its (nonzero) digits is 720, while the sum is 24.
Adding to 1121331210045 its reverse (5400121331211), we get a palindrome (6521452541256).
The spelling of 1121331210045 in words is "one trillion, one hundred twenty-one billion, three hundred thirty-one million, two hundred ten thousand, forty-five".
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