Base | Representation |
---|---|
bin | 10100111000101110… |
… | …11001000110101111 |
3 | 1001221110211021212211 |
4 | 22130113121012233 |
5 | 140431101444211 |
6 | 5052404111251 |
7 | 544606403656 |
oct | 123427310657 |
9 | 31843737784 |
10 | 11213312431 |
11 | 4834693662 |
12 | 220b395527 |
13 | 1099193119 |
14 | 78535a19d |
15 | 459677e21 |
hex | 29c5d91af |
11213312431 has 4 divisors (see below), whose sum is σ = 11216297664. Its totient is φ = 11210327200.
The previous prime is 11213312417. The next prime is 11213312443. The reversal of 11213312431 is 13421331211.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11213312431 - 25 = 11213312399 is a prime.
It is a super-2 number, since 2×112133124312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11213312531) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1486975 + ... + 1494496.
It is an arithmetic number, because the mean of its divisors is an integer number (2804074416).
Almost surely, 211213312431 is an apocalyptic number.
11213312431 is a deficient number, since it is larger than the sum of its proper divisors (2985233).
11213312431 is an equidigital number, since it uses as much as digits as its factorization.
11213312431 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2985232.
The product of its digits is 432, while the sum is 22.
Adding to 11213312431 its reverse (13421331211), we get a palindrome (24634643642).
The spelling of 11213312431 in words is "eleven billion, two hundred thirteen million, three hundred twelve thousand, four hundred thirty-one".
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