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112133130000 = 2435413727283
BaseRepresentation
bin110100001101110100…
…1111100011100010000
3101201102202021012121220
41220123221330130100
53314122040130000
6123302510045040
711046522610233
oct1503351743420
9351382235556
10112133130000
1143612257271
12198951a9780
13a7604175c8
1455da61541a
152db45061a0
hex1a1ba7c710

112133130000 has 200 divisors, whose sum is σ = 364636254048. Its totient is φ = 29682816000.

The previous prime is 112133129981. The next prime is 112133130023. The reversal of 112133130000 is 31331211.

It is a tau number, because it is divible by the number of its divisors (200).

It is a Harshad number since it is a multiple of its sum of digits (15).

It is an unprimeable number.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 4096359 + ... + 4123641.

Almost surely, 2112133130000 is an apocalyptic number.

112133130000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 112133130000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (182318127024).

112133130000 is an abundant number, since it is smaller than the sum of its proper divisors (252503124048).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

112133130000 is a wasteful number, since it uses less digits than its factorization.

112133130000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 27451 (or 27430 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 112133130000 its reverse (31331211), we get a palindrome (112164461211).

The spelling of 112133130000 in words is "one hundred twelve billion, one hundred thirty-three million, one hundred thirty thousand".