Base | Representation |
---|---|
bin | 11001011111110000001100… |
… | …110000011111101010000111 |
3 | 112201000211102220201010222001 |
4 | 121133300030300133222013 |
5 | 104144142313333000033 |
6 | 1034253142404050131 |
7 | 32422233505205416 |
oct | 3137601460375207 |
9 | 481024386633861 |
10 | 112133220203143 |
11 | 32802482552417 |
12 | 106b0204693947 |
13 | 4a7516a9008a9 |
14 | 1d993c382347d |
15 | ce6c980e2e7d |
hex | 65fc0cc1fa87 |
112133220203143 has 2 divisors, whose sum is σ = 112133220203144. Its totient is φ = 112133220203142.
The previous prime is 112133220203119. The next prime is 112133220203159. The reversal of 112133220203143 is 341302022331211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 112133220203143 - 25 = 112133220203111 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112133220203843) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56066610101571 + 56066610101572.
It is an arithmetic number, because the mean of its divisors is an integer number (56066610101572).
Almost surely, 2112133220203143 is an apocalyptic number.
112133220203143 is a deficient number, since it is larger than the sum of its proper divisors (1).
112133220203143 is an equidigital number, since it uses as much as digits as its factorization.
112133220203143 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 112133220203143 its reverse (341302022331211), we get a palindrome (453435242534354).
The spelling of 112133220203143 in words is "one hundred twelve trillion, one hundred thirty-three billion, two hundred twenty million, two hundred three thousand, one hundred forty-three".
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