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11213333130000 = 24354419116531
BaseRepresentation
bin1010001100101100111010…
…1111001110101100010000
31110200222120110120112201110
42203023032233032230100
52432204401240130000
635503200100533320
72235064563650421
oct243131657165420
943628513515643
1011213333130000
113633603248011
1213112766b1240
13634549b42561
142aaa2a33b648
15146a40435850
hexa32cebceb10

11213333130000 has 200 divisors, whose sum is σ = 37081019850336. Its totient is φ = 2917289600000.

The previous prime is 11213333129993. The next prime is 11213333130001. The reversal of 11213333130000 is 3133331211.

11213333130000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a tau number, because it is divible by the number of its divisors (200).

It is not an unprimeable number, because it can be changed into a prime (11213333130001) by changing a digit.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 3328266 + ... + 5788265.

Almost surely, 211213333130000 is an apocalyptic number.

11213333130000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

11213333130000 is an abundant number, since it is smaller than the sum of its proper divisors (25867686720336).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11213333130000 is an equidigital number, since it uses as much as digits as its factorization.

11213333130000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9116603 (or 9116582 counting only the distinct ones).

The product of its (nonzero) digits is 486, while the sum is 21.

Adding to 11213333130000 its reverse (3133331211), we get a palindrome (11216466461211).

The spelling of 11213333130000 in words is "eleven trillion, two hundred thirteen billion, three hundred thirty-three million, one hundred thirty thousand".