Base | Representation |
---|---|
bin | 1010001100101100111110… |
… | …1111101101010000111011 |
3 | 1110200222121122101021111212 |
4 | 2203023033233231100323 |
5 | 2432204420102014233 |
6 | 35503201503113335 |
7 | 2235065160425606 |
oct | 243131757552073 |
9 | 43628548337455 |
10 | 11213350032443 |
11 | 3633611842079 |
12 | 13112802a284b |
13 | 6345504acac0 |
14 | 2aaa2c69b33d |
15 | 146a41b73a48 |
hex | a32cfbed43b |
11213350032443 has 16 divisors (see below), whose sum is σ = 12885619934880. Its totient is φ = 9671677634304.
The previous prime is 11213350032427. The next prime is 11213350032473. The reversal of 11213350032443 is 34423005331211.
It is a cyclic number.
It is not a de Polignac number, because 11213350032443 - 24 = 11213350032427 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11213350032473) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 310928396 + ... + 310964457.
It is an arithmetic number, because the mean of its divisors is an integer number (805351245930).
Almost surely, 211213350032443 is an apocalyptic number.
11213350032443 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
11213350032443 is a deficient number, since it is larger than the sum of its proper divisors (1672269902437).
11213350032443 is a wasteful number, since it uses less digits than its factorization.
11213350032443 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 621892958.
The product of its (nonzero) digits is 25920, while the sum is 32.
Adding to 11213350032443 its reverse (34423005331211), we get a palindrome (45636355363654).
The spelling of 11213350032443 in words is "eleven trillion, two hundred thirteen billion, three hundred fifty million, thirty-two thousand, four hundred forty-three".
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