Base | Representation |
---|---|
bin | 10100111000101111… |
… | …00011011011110101 |
3 | 1001221110220102220212 |
4 | 22130113203123311 |
5 | 140431104322431 |
6 | 5052405035205 |
7 | 544606641221 |
oct | 123427433365 |
9 | 31843812825 |
10 | 11213354741 |
11 | 4834712426 |
12 | 220b3b5b05 |
13 | 10991a9464 |
14 | 78536b781 |
15 | 45968572b |
hex | 29c5e36f5 |
11213354741 has 2 divisors, whose sum is σ = 11213354742. Its totient is φ = 11213354740.
The previous prime is 11213354729. The next prime is 11213354759. The reversal of 11213354741 is 14745331211.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10992683716 + 220671025 = 104846^2 + 14855^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11213354741 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11213354698 and 11213354707.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11213354771) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606677370 + 5606677371.
It is an arithmetic number, because the mean of its divisors is an integer number (5606677371).
Almost surely, 211213354741 is an apocalyptic number.
It is an amenable number.
11213354741 is a deficient number, since it is larger than the sum of its proper divisors (1).
11213354741 is an equidigital number, since it uses as much as digits as its factorization.
11213354741 is an evil number, because the sum of its binary digits is even.
The product of its digits is 10080, while the sum is 32.
Adding to 11213354741 its reverse (14745331211), we get a palindrome (25958685952).
The spelling of 11213354741 in words is "eleven billion, two hundred thirteen million, three hundred fifty-four thousand, seven hundred forty-one".
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