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11213431181 is a prime number
BaseRepresentation
bin10100111000101111…
…10110000110001101
31001221111001022202222
422130113312012031
5140431114244211
65052410425125
7544610410121
oct123427660615
931844038688
1011213431181
1148347648a7
12220b4321a5
1310992051a4
1478538b581
1545969d1db
hex29c5f618d

11213431181 has 2 divisors, whose sum is σ = 11213431182. Its totient is φ = 11213431180.

The previous prime is 11213431121. The next prime is 11213431211. The reversal of 11213431181 is 18113431211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10170722500 + 1042708681 = 100850^2 + 32291^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11213431181 is a prime.

It is a super-2 number, since 2×112134311812 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 11213431181.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11213431111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5606715590 + 5606715591.

It is an arithmetic number, because the mean of its divisors is an integer number (5606715591).

Almost surely, 211213431181 is an apocalyptic number.

It is an amenable number.

11213431181 is a deficient number, since it is larger than the sum of its proper divisors (1).

11213431181 is an equidigital number, since it uses as much as digits as its factorization.

11213431181 is an evil number, because the sum of its binary digits is even.

The product of its digits is 576, while the sum is 26.

Adding to 11213431181 its reverse (18113431211), we get a palindrome (29326862392).

The spelling of 11213431181 in words is "eleven billion, two hundred thirteen million, four hundred thirty-one thousand, one hundred eighty-one".